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Let P be the point on the parabola, $y^2= 8x$ which is at a minimum distance from the centre $C$ of the circle, $x^2+(y + 6)^2= 1.$ Then the equation of the circle, passing through C and having its centre at P is:

$\begin{array}{1 1}(1)x^2+y^2-4x+8y+12=0 \\ (2)x^2+y^2-x+4y-12=0 \\ (3) x^2+y^2-\frac{x}{4}+2y-24=0 \\ (4)x^2+y^2-4x+9y+18=0\end{array} $

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