For three events A, B and C, P(Exactly one of A or B occurs) = P(Exactly one of B or C occurs) = P(Exactly one of C or A occurs) = $\frac{1}{4}$ and P (All the three events occur simultaneously) = $\frac{1}{6}$. Then the probability that at least one of the events occurs, is :

Question

( A ) $\frac{7}{64}$
( B ) $\frac{7}{32}$
( C ) $\frac{3}{16}$
( D ) $\frac{7}{16}$