Given : <br> $C_(graphite) + O_2(g) \to CO_2 (g) ; \; \; \; \; \Delta_r H^{\circ} = -393.5\; kJ \; mol^{-1};$ <br> $H_2(g) + \frac{1}{2}O_2(g) \to H_2O(l); \;\;\;\; \; \; \; \; \Delta_rH^{\circ} = -285.8 \; kJ\; mol^{-1};$ <br> $CO_2(g) + 2 H_2O (l) \to CH_4(g) + 2O_2 (g); \; \; \; \; \Delta_r H^{\circ} = + 890.3 \;kJ\; mol^{-1}$ <br> Based on the above thermochemical equations, the value of $\Delta_r H^{\circ}$ at 298 K for the reaction

Question

( A ) $-144.0 \; kJ\; mol^{-1}$
( B ) $+74.8 \; kJ \; mol^{-1}$
( C ) $-74.8 \; kJ \; mol^{-1}$
( D ) $+144.0 \; kJ\; mol^{-1}$