If $\mathrm{cosec} \theta = \frac{p+q}{p-q}$, then $\cot (\frac{\pi}{4} + \frac{\theta}{2} )$ is equal to :

Question

( A ) $\frac{\sqrt{p}}{q}$
( B ) $pq$
( C ) $\sqrt{pq}$
( D ) $\frac{\sqrt{q}}{p}$