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Let the line \frac{x-2}{3}=\frac{y-1}{-5}=\frac{z+2}{2} 3 x−2 =
Let the line \frac{x-2}{3}=\frac{y-1}{-5}=\frac{z+2}{2} 3 x−2 = −5 y−1 = 2 z+2 lie in the plane x+3 y-\alpha z+\beta=0 .x+3y−αz+β=0. Then (\alpha, \beta)(α,β) equals
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