Question

If the line \frac{x-2}{3}=\frac{y+1}{2}=\frac{z-1}{-1} 3 x−2 ​ = 2 y+1 ​ = −1 z−1 ​ intersects the plane 2 x+3 y-z+13=02x+3y−z+13=0 at a point PP and the plane 3 x+y+4 z=163x+y+4z=16 at a point \mathbf{Q},Q, then \mathbf{P Q}PQ is equal to