Find $\frac {dy}{dx}$ in the following: $\sin^2x +\cos^2y = 1$

Question

$\begin{array}{1 1}\large \frac{\sin\;2x}{\sin\;2y} \\ -\large \frac{\sin\;2x}{\sin\;2y} \\ \large \frac{\cos\;2x}{\cos\;2y} \\ -\large \frac{\cos\;2x}{\cos\;2y} \end{array}$