The sum of n terms of the infinite series $1.3^2$+$2.5^2$+$3.7^2$+-------$\infty$ is given by

Question

$\begin{array}{1 1} \frac{n}{6(n+1)(6n^2+14n+7)} \\ \frac{n}{6(n+1)(2n+1)(3n+1)} \\4n^3+4n^2+n \\ [\frac{n(n+1)}{2}]^2\end{array}$