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JEEMAIN and NEET
>>
Mathematics
>>
Class12
>>
Differential Equations
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Q)
Solution of differential equation:
X
2
=
1
+
1
2
(
x
y
)
−
1
d
y
d
x
+
(
x
y
)
−
2
(
d
y
d
x
)
2
4
×
2
×
1
+
(
x
y
)
−
3
(
d
y
d
x
)
3
8
×
3
×
2
×
1
+
(
x
y
)
−
4
(
d
y
d
x
)
4
16
×
4
×
3
×
2
×
1
+
.
.
.
.
.
.
.
.
.
.
(
a
)
y
2
=
2
x
2
(
log
x
2
−
1
)
+
c
(
b
)
y
=
2
x
2
(
log
x
−
1
)
+
c
(
c
)
y
2
=
2
x
2
(
log
x
−
1
)
+
c
(
d
)
y
=
2
x
2
e
x
2
−
1
)
+
c
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