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JEEMAIN and NEET
>>
Physics
>>
Class12
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Electric Charges and Fields
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Q)
Let
ε
0
denote the dimensional formula of the permittivity of vacuum. If M = mass, L = length and T = time and A = electric current then,
(
A
)
[
ε
0
]
=
[
M
−
1
L
−
3
T
4
A
2
]
(
B
)
[
ε
0
]
=
[
M
−
1
L
2
T
−
1
A
−
2
]
(
C
)
[
ε
0
]
=
[
M
−
1
L
2
T
−
1
A
]
(
D
)
[
ε
0
]
=
[
M
−
1
L
−
3
T
2
A
]
Share
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