EMF of following cell is 0.67V at 298K $Pt/H_2(1atm)/H^+(pH=X)\parallel KCl(1N)/Hg_2Cl_2(s)/Hg$.Calculate pH of anode compartment.Given : $E^0_{Cl^-/Hg^2Cl_2/Hg}=0.28V$.

Question

$\begin{array}{1 1}(a)\;5\\(b)\;6.6\\(c)\;6\\(d)\;7\end{array}$