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Questions  >>  JEEMAIN and NEET  >>  Physics  >>  Class12  >>  Atoms
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Q)

A deuterium reaction that occurs in an experimental fusion reactor is in two stapes
(1) Two deuterium nucli fuse together to form a tritium nucleus , with a proton as a by-product written as 1>(D,P)T.
(2) A tritium nucleus fuses with another oleunterium nucleus to form a helium 2He4 nucleus with neutron as a-by-product written as T(D,n)2He4. Then the energy released in each of two stages and energy released in combined reaction is
Given
1D2=2.014102a.m.u
1T3=3.016049a.m.u
1H1=1.007825a.m.u
1n1=1.008665a.m.u

(a)5.03MeV(b)6.03MeV(c)7.03MeV(d)4.03MeV

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