A deuterium reaction that occurs in an experimental fusion reactor is in two stapes (1) Two deuterium nucli fuse together to form a tritium nucleus , with a proton as a by-product written as $\; 1 > (D ,P)\; T\;.$ (2) A tritium nucleus fuses with another oleunterium nucleus to form a helium $\;_{2}He^{4}\;$ nucleus with neutron as a-by-product written as $\;T (D,n)\;_{2}He^{4}\;.$ Then the energy released in each of two stages and energy released in combined reaction is Given $\;_{1}D^{2}=2.014102\;a.m.u$ $\;_{1}T^{3}=3.016049\;a.m.u$ $\;_{1}H^{1}=1.007825\;a.m.u$ $\;_{1}n^{1}=1.008665\;a.m.u$ The energy released per deuterium nuclei is

Question

$(a)\;29.3 MeV\qquad(b)\;24.4 MeV\qquad(c)\;21.6 MeV\qquad(d)\;18.6 MeV$