Given below are the half - cell reactions $$\begin{array}{1 1}Mn^{2+}+2e^-\rightarrow Mn;E^{\large\circ}=-1.18V\\2(MN^{3+}+e^-\rightarrow Mn^{2+});E^{\large\circ}=-1.18V\end{array}$$ The $E^{\large\circ}$ for $3Mn^{2+}\rightarrow Mn+2Mn^{3+}$ will be

Question

$\begin{array}{1 1}(A)\;-0.33V;\text{the reaction will not occur}\\(B)\;-0.33V;\text{the reaction will occur}\\(C)\;-2.69V;\text{the reaction will not occur}\\(D)\;-2.69V;\text{the reaction will occur}\end{array}$