If $x=a(\theta-\sin \theta).y=a(1-\cos \theta) \;then\; \Large\frac{d^2y}{dx^2}\;\normalsize at\;\theta=\Large\frac{\pi}{2}\;is.$ $$(a)\;\frac{1}{a}\qquad(b)\;\frac{1}{2}\qquad(c)\;-\frac{1}{a}\qquad(d)\;-\frac{1}{2a}\qquad$$

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