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JEEMAIN and NEET
>>
Physics
>>
Class11
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Mechanical Properties of Solids
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Q)
A steel rod of r=30mm and length 3m.A 50 KN force is applied along its length.Calculate the change in length is
Y
=
2
×
10
11
N
/
m
2
(
A
)
0.52
m
m
(
B
)
0.23
m
m
(
C
)
0.26
m
m
(
D
)
0.50
m
m
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