What is the pressure inside the drop of mercury of radius 3mm at room temperature?S.T of mercury at that temperature $(20^{\large\circ}C)$ is $4.65\times 10^{-1}Nm^{-1}$.The $P_{atm}=1.01\times 10^4pa$.Also give excess pressure inside the drop

Question

$\begin{array}{1 1}(A)\;1.01\times 10^5pa;310pa\\(B)\;1\times 10^5pa;220pa\\(C)\;3\times 10^5pa;330pa\\(D)\;1\times 10^5pa;300pa\end{array} $