$\int \sqrt {1+x^2} d(x^2)=$\[(a)\;\frac{2}{3x}(1+x^2)^{3/2}\qquad (b)\;\frac{2}{3}(1+x^2)^{3/2}\qquad(c)\;\frac{2x}{3}(1+x^2)^{3/2}\qquad(d)\;\frac{2x}{3}(1+x^2)\]

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