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Questions  >>  CBSE XI  >>  Math  >>  Probability
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A sample space consists of a elementary outcomes $e_1,e_2........e_9$ whose probabilities are $P(e_1)=P(e_2)=0.08,P(e_3)=P(e_4)=P(e_5)=.1,P(e_6)=P(e_7)=.2,P(e_8)=p(e_9)=0.07$.Suppose $A=\{e_1,e_5,e_8\},B=\{e_2,e_5,e_8,e_9\}$.Calculate P(A),P(B) and $P(A \cap B)$

$\begin{array}{1 1}(A)\;0.25,0.32,0.17\\(B)\;0.35,0.42,0.27\\(C)\;0.45,0.42,0.37\\(D)\;\text{None of these}\end{array} $

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