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Questions  >>  JEEMAIN and NEET  >>  Chemistry  >>  Solutions
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The molar mass and the freezing point of camphor are $152.2\;g\;mol^{-1} $ and $178.4^{\circ} C $ respectively . The cryoscopic constant of camphor is $ 37.7\;K\;kg\;mol^{-1}$, the molar enthalpy of fusion of camphor is about

$\begin{array}{1 1} 5.24\;kJ\;K^{-1}\;mol^{-1} \\ 6.84\;kJ\;K^{-1} \;mol^{-1} \\ 8.24\;kJ\;K^{-1}\;mol^{-1} \\ 9.8 \;kJ K^{-1} mol^{-1} \end{array} $

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