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JEEMAIN-2014
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Three of the six vertices of a regular hexagon are chosen at random . The probability that the triangle with these three vertices equilateral equals
$\begin{array}{1 1} \large\frac{1}{2} \\ \large\frac{1}{5} \\ \large\frac{1}{10} \\ \large\frac{1}{20} \end{array} $
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