The distance of the point $(1,0,2)$ from the point of intersection of the line $ \large\frac{x-2}{3} =\frac{y+1}{4} =\frac{z-2}{12}$ and the plane $x-y+z=16$, is:

Question

$\begin{array}{1 1} 2 \sqrt {14} \\ 8 \\ 3\sqrt{21} \\ 13 \end{array} $