The distance of the point $(1,0,2) $ from the point of intersection of the line $ \large\frac{x-2}{3}=\frac{y+1}{4}=\frac{z-2}{12}$ and the plane $x-y+z=16$ , is:

Question

$\begin{array}{1 1} 8 \\ 3\sqrt {21} \\13 \\ 2 \sqrt{14} \end{array} $