If $\int f(x)=dx= \psi(x)$, then $\int x^5 f(x^3)dx $ is equal to :

Question

$\begin{array}{1 1} (1) \large\frac{1}{3}[x^3 \psi (x^3)- \int x^2 \psi (x^3)dx ]+C \\ (2) \large\frac{1}{3}[x^3 \psi (x^3)-3\int x^3 \psi (x^3)dx ]+C \\ (3) \large\frac{1}{3} x^3 \psi (x^3)- \int x^2 \psi (x^3)dx +C \\ (4) \frac{1}{3} [x^3 \psi (x^3) -\int x^3 \psi (x^3) dx ]+C\end {array}$