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Questions  >>  JEEMAIN and NEET  >>  NEET PAST PAPERS  >>  2017
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A spring of force constant k is cut into lengths of ratio $I : 2 :3$ . They are connected in series and the, new force constant is 'K'.- Then they are connected is parallel and force constant is k". Then k, : k, is

$\begin{array}{1 1} (1) 1:6\\ (2) 1:9 \\ (3)1:11 \\ (4) 1:14 \end{array} $

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