Recent questions in Inverse Trigonometric Functions

Find the value of $tan\frac{1}{2} \bigg[ sin^{-1} \frac{2x}{1+x^2} + cos^{-1} \frac{1-y^2}{1+y^2} \bigg], | x | < 1, y > 0 \: and \: xy < 1$

asked Dec 10, 2012 by thanvigandhi_1

1 answer

Find the value of $x$ if $sin \bigg ( sin^{-1} \frac{1}{5} + cos^{-1} \: x \bigg) = 1$ .

asked Dec 10, 2012 by thanvigandhi_1

1 answer

If $\tan^{-1} \frac{\large x-1}{\large x-2} + \tan^{-1} \frac{\large x+1}{\large x+2} = \frac{\large \pi}{\large 4}$ then find the value of $x$

asked Dec 10, 2012 by thanvigandhi_1

1 answer

Find the values of $sin^{-1} \bigg( sin \frac{2\pi}{3} \bigg)$

asked Dec 10, 2012 by thanvigandhi_1

1 answer

Find the value of the expression in $tan^{-1} \bigg( tan \frac{3\pi}{4} \bigg)$

asked Dec 10, 2012 by thanvigandhi_1

1 answer

Find the values of the expression $\tan \bigg( \sin^{-1} \frac{3}{5} + \cot^{-1} \frac{3}{2} \bigg)$

asked Dec 10, 2012 by thanvigandhi_1

1 answer

Find the value of the expression $\cos^{-1} \bigg(\cos \frac{\large 7\pi}{\large 6} \bigg)$

asked Dec 10, 2012 by thanvigandhi_1

1 answer

Find the values of each of the expressions in $\sin \bigg(\frac{\pi}{3} - \sin^{-1} ( -\frac{1}{2} ) \bigg)$ is equal to

asked Dec 10, 2012 by thanvigandhi_1

1 answer

Find the value of $\tan^{-1} \sqrt 3 - \cot^{-1} (-\sqrt 3)$

asked Dec 10, 2012 by thanvigandhi_1

1 answer

Find the value of: $\cos^{-1} (\cos \large\frac{13\pi}{6} )$

asked Dec 10, 2012 by thanvigandhi_1

1 answer

Find the value of the following: $tan^{-1} \bigg(tan \frac{7\pi}{6}\bigg)$

asked Dec 10, 2012 by thanvigandhi_1

1 answer

What does $2\sin^{-1} \frac{3}{5}$ reduce to

asked Dec 10, 2012 by thanvigandhi_1

1 answer

Prove the following $3\sin^{-1}x=\sin^{-1}(3x-4x^3)\;x\in\bigg[-\frac{1}{2},\frac{1}{2}\bigg]$

asked Dec 6, 2012 by sreemathi.v

1 answer

Prove the following $3\cos^{-1}x=\cos^{-1}(4x^3-3x), \;x\;\in\bigg[\frac{1}{2},1\bigg]$

asked Dec 6, 2012 by sreemathi.v

1 answer

Prove the following $\tan^{-1}\frac{2}{11}+\tan^{-1}\frac{7}{24}=\tan^{-1}\frac{1}{2}$

asked Dec 6, 2012 by sreemathi.v

1 answer

Prove that $sin^{-1} \frac{8}{17} +sin^{-1} \frac{3}{5} =tan^{-1} \frac{77}{36}$

asked Nov 29, 2012 by vaishali.a

1 answer

Prove that $cos^{-1} \frac {4}{5} +cos^{-1} \frac{12}{13}=cos^{-1} \frac{33}{65}$

asked Nov 29, 2012 by vaishali.a

1 answer

Prove that $cos^{-1} \frac {12}{13} +sin^{-1} \frac{3}{5}=sin^{-1} \frac{56}{65}$

asked Nov 29, 2012 by vaishali.a

1 answer

What does $\sin^{-1} \frac{5}{13}+\cos^{-1} \frac {3}{5}$ reduce to?

asked Nov 29, 2012 by vaishali.a

1 answer

Prove that $tan^{-1} \frac{1}{5}+ tan^{-1} \frac{1}{7}+tan^{-1}\frac{1}{3}+tan^{-1} \frac{1}{8}= \frac{\pi}{4}$

asked Nov 29, 2012 by vaishali.a

1 answer

Prove that $tan^{-1} \sqrt{x} = \frac{1}{2} cos^{-1} \;\; \bigg(\frac{1-x}{1+x}\bigg), x\in [0,1]$

asked Nov 29, 2012 by vaishali.a

1 answer

prove that $tan^{-1} \left ( \frac {{\sqrt {1+x}}-{\sqrt {1-x}}}{{\sqrt {1+x}}+{\sqrt {1-x}}} \right ) = \frac {\pi}{4} -\frac{1}{2} cos^{-1}x,-\frac{1}{\sqrt2} \leq x \leq 1$

asked Nov 29, 2012 by vaishali.a

1 answer

Prove that $cot^{-1} \left ( \frac {{\sqrt {1+sinx}}+{\sqrt {1-sinx}}}{{\sqrt {1+sinx}}-{\sqrt {1-sinx}}} \right ) = \frac {x}{2} , x \in \left ( 0, \frac{\pi}{4} \right )$

asked Nov 29, 2012 by vaishali.a

1 answer

Prove that $\frac{9 \pi}{8} - \frac{9}{4} sin ^{-1}\frac{1}{3}= \frac{9}{4} sin^{-1}\frac{2\sqrt 2}{3}$

asked Nov 29, 2012 by vaishali.a

1 answer

Solve the following $2tan^{-1} (cos x) = tan^{-1} (2\, cosec\, x)$

asked Nov 29, 2012 by vaishali.a

1 answer