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$e^{(x-1) - \frac{1}{2} (x-1)^2 + \frac{(x-1)^3}{3} - \frac{(x-1)^4}{4} + . . . } $ equal to :

asked Dec 11, 2018 by pady_1

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A couple is of momen $\overrightarrow{G}$ and the force forming the couple is $\overrightarrow{P}$. If $\overrightarrow{P}$ is turned through a right angle, the moment of the couple thus formed is $\overrightarrow{H}$. If instead, the forcce $\overrightarrow{P}$ is turned through an angle $\alpha$, then the moment of couple becomes :

asked Dec 11, 2018 by pady_1

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For a transistor amplifier in common emitter configuration having load impedance of $1 \; k \Omega\; (h_{fe} = 50$ and $h_{oe} = 25)$ the current gain is

asked Nov 5, 2018 by pady_1

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