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To divide a line segment $AB$ in the ration $s : t$ (s and t are positive integers with $s : t $$9\; s$ and t are positive integers with $s > t)$, draw a ray AX so that $ \angle BAX$ is an acute angle and then mark points on the ray $AX$ at equal distances such that the minimum number of these points is:
olympiad
class10
math
ch7
constructions
asked
Aug 1, 2016
by
meena.p
1
answer
To construct a triangle similar to given $\Delta ABC$ with its sides $\large\frac{7}{5}$ of the corresponding side of $\Delta ABC$ draw a ray $BX$ such that $\angle CBX$ is an acute angle and $X$ is on the opposite side of $A$ with respect to $BC$. Then, locate points $X_1,X_2,X_3…$ at equal distances on $BX$. The points to be joined in the next step are
olympiad
class10
math
ch7
constructions
asked
Aug 1, 2016
by
meena.p
1
answer
To divide a line segment $LM$ in the ratio $4 : 3$, a ray $LX$ is drawn firs such that $\angle MLX$ is an acute angle and then points $L_1, L_2, L_3, …$ are located at equal distances on the ray $LX$ and the points $M$ is joined to :
olympiad
class10
math
ch7
constructions
asked
Aug 1, 2016
by
meena.p
1
answer
To divide a line segment $AB$ in the ration $4 : 7$, a ray $AX$ is drawn first such that $\angle BAX$ is an acute angle and then points $A_1,A_2,A_3,…$ are located at equal distances on the ray $AX$ and the point $B$ is joined to :
olympiad
class10
math
ch7
constructions
asked
Aug 1, 2016
by
meena.p
1
answer
To divide a line segment AB in the ratio $p : q ( p, q$ are positive integers), draw a ray $AX$ so that $\angle BAX$ $s$ an acute angle and then mark points on ray $AX$ at equal distances such that the minimum number of these points is :
olympiad
class10
math
ch7
constructions
asked
Aug 1, 2016
by
meena.p
1
answer
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