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Recent questions tagged integration-by-subsitution
Questions
Integrate : $\int \large\frac{1}{1+\cos x }$$ dx$
jeemain
math
class12
ch7
integral-calculus
integration-by-subsitution
easy
q71
asked
Dec 17, 2013
by
meena.p
1
answer
Integrate :$\int \large\frac{1}{1+\cos x}$$dx$
jeemain
math
class12
ch7
integral-calculus
integration-by-subsitution
easy
q69
asked
Dec 17, 2013
by
meena.p
1
answer
$\int \limits_0^a x dx < a+4$ then
jeemain
math
class12
ch7
integral-calculus
integration-by-subsitution
easy
q67
asked
Dec 17, 2013
by
meena.p
1
answer
$\int \limits_0^{x^2} t.f(t).dt =\large\frac{2}{5}.$$x^3$ then find $f\bigg(\large\frac{4}{25}\bigg)$
jeemain
math
class12
ch7
integral-calculus
integration-by-subsitution
easy
q40
asked
Dec 14, 2013
by
meena.p
1
answer
$I_1= \int \limits_{(-2-k)}^{k+3} x f[x (1-x)].dx; \; I_2= \int \limits_{(-2-k)}^{k+3} x f[x (1-x)].dx; \; \large\frac{I_1}{I_2}=?$
jeemain
math
class12
ch7
integral-calculus
integration-by-subsitution
medium
q30
asked
Dec 13, 2013
by
meena.p
1
answer
$I_1= \int \limits _0^{\pi} x \log \sin x dx;\; I_2=\int \limits_0^{\pi} \log \sin x dx . $ find $\large\frac{I_1}{I_2}$=?
jeemain
math
class12
ch7
integral-calculus
integration-by-subsitution
easy
q25
asked
Dec 13, 2013
by
meena.p
1
answer
Integrate : $\int \limits_0^{\infty} \large\frac{\log x}{1+x^2}$$dx$
jeemain
math
class12
ch7
integral-calculus
integration-by-subsitution
medium
q23
asked
Dec 13, 2013
by
meena.p
1
answer
$\int \limits_1^4 \large\frac{2 e^{\Large \sin x^2}}{x}$$=f(k)-f(1)$ then find $k$=? if $\large\frac{d}{dx}$$f(x)=\Large\frac{e^{\sin x }}{\normalsize x}$
jeemain
math
class12
ch7
integral-calculus
integration-by-subsitution
medium
q12
asked
Dec 12, 2013
by
meena.p
1
answer
Integrate : $\int \limits_0^{\large\frac{z}{2}}$$ \cos x \sin ^3 x dx$
jeemain
math
class12
ch7
integral-calculus
integration-by-subsitution
medium
q11
asked
Dec 12, 2013
by
meena.p
1
answer
Integrate: $\int \limits_0^{z/4} \sin ^4 (2x)dx $
jeemain
math
class12
ch7
integral-calculus
integration-by-subsitution
easy
q8
asked
Dec 12, 2013
by
meena.p
1
answer
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