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Recent questions tagged p199
Questions
The solution of the equation $(2y-1)dx-(2x+3)dy=0$ is\[(A)\;\frac{2x-1}{2y+3}=k \quad (B)\;\frac{2y+1}{2x-3}=k \quad (C)\;\frac{2x+3}{2y-1}=k \quad (D)\;\frac{2x-1}{2y+1}=k \]
cbse
class12
ch9
sec-a
q64
p199
objective
exemplar
medium
math
asked
Jan 20, 2013
by
sreemathi.v
1
answer
The general solution of the differential equation $\large\frac{dy}{dx} $$=e^{\large\frac{x^2}{2}}+xy$ is :\[(A)\;y=ce^{\large\frac{x^2}{2}} \quad (B)\;y=-ce^{\large\frac{x^2}{2}} \quad (C)\;y=(x+c)e^{\large\frac{x^2}{2}} \quad (D)\;y=(c-x)e^{\large\frac{x^2}{2}}\]
cbse
class12
ch9
sec-a
q63
p199
objective
exemplar
medium
math
asked
Jan 19, 2013
by
sreemathi.v
1
answer
The curve for which the slope of the tangent at any point is equal to the ratio of the abscissa to the ordinate of the point is
class12
cbse
ch9
sec-a
q62
p199
objective
exemplar
easy
jeemain
differential-equations
math
asked
Jan 19, 2013
by
sreemathi.v
1
answer
The general solution of $\large\frac{dy}{dx}$$=2xe^{x^2-y}$ is: \[(A)\;e^{x^2-y}=c \quad (B)\;e^{-y}+e^{x^2}=c \quad(C)\;e^y=e^{x^2}+c \quad (D)\;e^{x^2}+y=c\]
cbse
class12
ch9
sec-a
q61
p199
objective
exemplar
easy
math
asked
Jan 19, 2013
by
sreemathi.v
1
answer
Family $Y=Ax+A^3$ of curves will correspond to a differential equation of order \[(A)\;3\quad(B)\;2\quad(C)\;1\;(D)\;not\;defined\]
cbse
class12
ch9
sec-a
q60
p199
objective
exemplar
easy
math
asked
Jan 19, 2013
by
sreemathi.v
1
answer
The differential equation of the family of curves $x^2+y^2-2ay=0$,where a is arbitrary constant,is\[(A)\;(x^2-y^2)\frac{dy}{dx}=2xy \quad (B)\;2(x^2+y^2)\frac{dy}{dx}=xy \quad (C)\;2(x^2-y^2)\frac{dy}{dx}=xy \quad (D)\;2(x^2+y^2)\frac{dy}{dx}=2xy\]
cbse
class12
ch9
sec-a
q59
p199
objective
exemplar
medium
math
asked
Jan 19, 2013
by
sreemathi.v
1
answer
Choose the correct answer in the total revenue in Rupees received from the sale of $x$ units of a product is given by $Rx = 3x^2 +36x + 5$. The marginal revenue, when $x = 15$ is
cbse
class12
bookproblem
ch6
sec1
q18
p199
sec-a
easy
math
asked
Nov 23, 2012
by
thanvigandhi_1
1
answer
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