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Recent questions tagged p23

$\Large\int x^3 e^{x^2} dx=$ \[(a)\;x^2(e^{x^2}-1) \qquad (b)\;\frac{1}{2}x^2(e^{x^2}-1)\qquad(c)\;\frac{1}{2}e^{x^2}(x^2-1) \qquad(d)\;\frac{1}{2}(e^x-1)\]

asked Jan 30, 2013 by meena.p

0 answers

$\Large\int \frac {\sqrt x}{\sqrt{a^3-x^3}} dx=$\[(a)\;\frac{2}{3}\bigg(\frac{x}{a}\bigg)^{3/2} \qquad (b)\;\frac{2}{3}\sin^{-1}\bigg(\frac{x}{a}\bigg)^{3/2} \qquad(c)\;\frac{2}{3}\cos {-1}\bigg(\frac{x}{a}\bigg)^{3/2} \qquad(d)\;\frac{2}{3}\sin^{-1}\bigg(\frac{a}{x}\bigg)^{3/2}\]

asked Jan 30, 2013 by meena.p

0 answers

$\Large\int \frac {e^xdx} {e^{2x}+1}=$\[(a)\;log (e^x+e^{-x}) \qquad (b)\;log (e^{2x}+1)\qquad(c)\;\tan^{-1}(e^x) \qquad(d)\;\tan^{-1}(2e^x)\]

asked Jan 30, 2013 by meena.p

0 answers

$\Large\int \frac {\sin^2xdx}{a^2\cos ^2x+b^2\sin^2x \sin^2 x} =$\begin{array}{1 1}(a)\;(b-a)log(a^2\cos ^2x+b^2\sin^2x) & \quad (b)\;\frac{1}{b-a}log(a^2\cos ^2x+b^2\sin^2x) & \\(c)\;\frac{1}{b^2-a^2}log(a^2\cos ^2x+b^2\sin^2x) & \quad(d)\;\frac{1}{a^2+b^2}log(a^2\cos ^2x+b^2\sin^2x)\end{array}

asked Jan 30, 2013 by meena.p

0 answers

$\Large\int \frac {dx}{\sin x+\sqrt 3 \cos x} =$ \begin{array}{1 1}(a)\;\frac{1}{2} log \tan \bigg [\frac{\pi}{2}+\frac{\pi}{6}\bigg] & \quad (b)\;\frac{1}{2} log \bigg\{cosec \bigg(x+\frac{\pi}{3}\bigg)-\cot \bigg(x+\frac{\pi}{3}\bigg)\bigg\} & \\ (c)\;\frac{1}{2} log \bigg\{\sec \bigg(x-\frac{\pi}{6}\bigg)+\tan \bigg(x-\frac{\pi}{6}\bigg)\bigg\} & \quad (d)\;-\frac{1}{2} log \bigg\{cosec \bigg(x+\frac{\pi}{3}\bigg)+\cot \bigg(x+\frac{\pi}{3}\bigg)\bigg\}\end{array}

asked Jan 30, 2013 by meena.p

0 answers

$\Large\int \frac {\sqrt {\tan x}}{\sin x \cos x} \normalsize dx=$\[(a)\;2\sqrt {\tan x} \qquad (b)\;2\sqrt {\cot x} \qquad(c)\;\sqrt {\cot x} \qquad(d)\;\sqrt {\tan x}\]

asked Jan 30, 2013 by meena.p

0 answers

$\Large\int \frac {\tan (log)x} {x} dx=$\[(a)\;log\cos (log x) \qquad (b)\;log\sec (log x)\qquad(c)\;log\sin (log x) \qquad(d)\;-log\cos (log x)\]

asked Jan 30, 2013 by meena.p

0 answers

choose the correct alternative$ \int \large\frac {\cos \sqrt x}{\sqrt x} dx=$\[(a)\;\sin \sqrt x \qquad (b)\;2\cos \sqrt x\qquad(c)\;2\sin \sqrt x \qquad(d)\;\large\frac{\sqrt \cos x}{x}\]

asked Jan 30, 2013 by meena.p

0 answers

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