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Recent questions tagged telegram-1568

(chatquestion)...The trajectory of a projectile in a vertical plane is y= ax – ßx² where a and ß are constants and x and y are respectively the - horizontal and vertical distances of the projectile from the point of projection. The maximum height attended by projectile is (A) (B) 28 B (D) 2a (C)

asked May 23, 2020 by balaji.thirumalai

1 answer

(chatquestion)...X+1 log/2 log3 X-1

asked Mar 29, 2020 by balaji.thirumalai

0 answers

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