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Recent questions tagged telegram-55829
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(chatquestion)...A particle oscillates with amplitude A in a one-dimensional potential U (x) that is symmetric about x = 0, i.e. U (x) = U(-x). (a) Show, from energy considerations, that the velocity v of the particle at displacement x from the equilibrium position (x = 0), is given by v = /2[U (A) – U(x)]/m. (b) Hence show that the period of oscillation T is given by dx T = 4, V[I- U(x)/U(A)] 2U (A) Simple Harmonic Motion (c) If the potential U (x) is given by U (x) = ax" where a is a constant and n = 2, 4, 6, ..., obtain the dependence of the period T on the amplitude A for different values of n = 2, 4, .... (Hint: Introduce the new variable of integration = x/A in the above expression for the period T.)
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telegram-55829
asked
Feb 8, 2020
by
balaji.thirumalai
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