A $ \times $ (B $ \cap $ C) ={(1, 4), (2, 4), (3, 4)}

(A $ \times $ B) $ \cup $ (A $ \times $ C) = {(1,3), (1,4), (1,5), (1,6), (2,3), (2,4), (2,5), (2, ...

A $ \times $ (B $ \cup $ C) = = {(1, 3), (1, 4), (1, 5), (1, 6), (2, 3), (2, 4), (2, 5), (2, 6), (3...

{(2, 1), (2, 3), (5, 1), (5, 3), (11, 1), (11, 3)}Hence (A) is the correct answer.

(–1, –1), (–1, 1), (0, –1), (0, 0), (1, –1), (1, 0), and (1, 1)

x, y, and z are the elements of A; and 1 and 2 are the elements of B.

16 subjects

A = {a, b} and B = {x, y}

(1, –1, –1), (1, –1, 1), (1, 1, –1), (1, 1, 1)}

True

True

False, P $ \times $ Q = {(m, m), (m, n), (n, m), (n, n)}

G $ \times $ H = {(7, 5), (7, 4), (7, 2), (8, 5), (8, 4), (8, 2)} H $ \times $ G = {(5, 7), (5, 8),...

(A $ \times $ B) is 9.

x = 2 and y = 1

A = set of first elements = {p, m} B = set of second elements = {q, r}.

The Cartesian product R $ \times $ R represents the set R $ \times $ R={(x, y) : x, y $ in $ R} whi...

We have, P $ \times $ P $ \times $ P = {(1,1,1), (1,1,2), (1,2,1), (1,2,2), (2,1,1), (2,1,2), (2,2...

Using the sets A $ \times $ B and A $ \times $ C from part (ii) [ i.e., Now (A $ \times $ B) = {(1,...

Since, (B $ \cup $ C) = {3, 4, 5, 6}, we have A $ \times $ (B $ \cup $ C) = {(1,3), (1,4), (1,5), ...

Now (A $ \times $ B) = {(1,3), (1,4), (2,3), (2,4), (3,3), (3,4)} and (A $ \times $ C) = {(1,4), ...

By the definition of the intersection of two sets, (B $ \cap $ C) = {4}.Therefore, A $ \times $ (B $...

Since the ordered pairs are equal, the corresponding elements are equal. Therefore x + 1 = 3 and y –

By the definition of the Cartesian product, P $ \times $ Q = {(a, r), (b, r), (c, r)} and Q $ \times...

{x : x $ \neq $ x}Hence (D) is the correct answer.

(A $ \cup $ B) – (A $ \cap $ B)Hence (C) is the correct answer.

None

60 percentHence (C) is the correct answer.

3300Hence (B) is the correct answer.

300Hence (C) is the correct answer.

YHence (B) is the correct answer.

A $ \cap $ B = $ \phi $Hence (C) is the correct answer.

AHence (A) is the correct answer.

(B) {1, 2, 3, 4}Hence (B) is the correct answer.

4Hence (B) is the correct answer.

2nHence (C) is the correct answer.

$ \phi $Hence (A) is the correct answer.

{x : x is a real number and $x^2$ + 1 = 0}Hence (B) is the correct answer.

Not a well defined collectionHence (D) is the correct answer.

((X – A) $ \cap $ (X – B)) = (A $ \cup $ B)$^C$A $ \times $ B = (A $ \cap $ B) $ \cup $ ((X – A)

P $ \cup $ Q = {1, 2, {1}, {2}}

Q = {{1}, {2}}

P = {1, 2}

https://clay6.com/mpaimg/cc35.jpgWhen B $ \subset $ A A $ \cup $ B = A

https://clay6.com/mpaimg/cc34.jpgWhen A $ \subset $ B ; A $ \cup $ B = B

A $ \cap $ B = B

n(A $ \cup $ B) = n(A) + n(B), provided A $ \cap $ B = $ \phi $

If A $ \subset $ B, B $ \subset $ C then X $ \in $ A implies X $ \in $ C.

If A $ \cap $ B = $ \phi $ , then (A $ \cup $ B) $ \cap $ (A $ \cap $ B) = $ \phi $

n(A $ \cap $B) = n (A) + n(B) – n(A $ \cup $ B)