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Answers posted by thanvigandhi_1

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answered Jun 28, 2014
https://clay6.com/mpaimg/15i.jpg
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answered Jun 28, 2014
Graph of f(x) = xhttps://clay6.com/mpaimg/14.jpg
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answered Jun 28, 2014
Domain of f is [– 3, 3], Range of f = [0, 3]
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answered Jun 28, 2014
Domain of f is R – {2} , Range of f is R – {– 1},
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answered Jun 27, 2014
Range of f = R - $ \bigg\{ \large\frac{ 5}{2} \bigg\}$
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answered Jun 27, 2014
–1 $ \leq $ x $ \leq $ 2.
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answered Jun 27, 2014
Domain of f = {x : x /x $ \geq $ 2, x $ \in $ R$^+$} (since if x < 2, f(x) will be an imaginary ...
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answered Jun 27, 2014
‘f’ is not a function.
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answered Jun 27, 2014
Domain of f(x) is {x : –3 ≤ x ≤ 3} or [–3, 3], Range of f(x) is {x: 0 ≤ x ≤ 3} or [0, 3].
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answered Jun 27, 2014
Domain of f is R, Range of f is (-$ \infty $, 0].
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answered Jun 26, 2014
We have (f + g) (x) = $ \sqrt x + x, (f-g) (x) = \sqrt x - x$$(fg)x= \sqrt x (x)=x^{\large\frac{...
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answered Jun 26, 2014
We have, f + g (x) = f(x) + g(x) = $x^2$ + 2x + 1, Similarly (f –g) (x) = $x^2$ – 2x – 1, (fg) (x)
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answered Jun 26, 2014
We have f(0) = 0, f(1) = 1, f(–1) = –1, f(2) = 8, f(–2) = –8, f(3) = 27; f(–3) = –27, etc.Therefore
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answered Jun 26, 2014
{(-2, 4), (-1, 1), (0, 0), (1, 1), (2, 4)}Hence (C) is the correct answer.
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answered Jun 26, 2014
Range of R is a subset of co-domain of R.Hence (B) is the correct answer.
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answered Jun 26, 2014
$R_4$ = {(3, 3), (5, 2), (5, 3), (7, 8)}Hence (D) is the correct answer.
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