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Questions  >>  JEEMAIN and NEET  >>  Physics  >>  Class12  >>  Alternating Current
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The Voltage time (V-t) graph of triangular wave having peak value $V_0$ is shown. The rms value of V in interval $t=0$ to $t=\large\frac{\pi}{4}$ is

$(a)\;\frac{V_o}{\sqrt 3}\\(b)\;\frac{V_o}{2}\\ (c)\;\frac{V_o}{\sqrt 2} \\ (d)\;none\;of\;them $

How do you get the wave
equation: V=(Vo)(t)/(T/4)

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