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Recent questions in Differential Equations
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JEEMAIN and NEET
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Mathematics
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Class12
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Differential Equations
If $x= \sec \theta -\cos \theta $ and $y=\sec^n \theta -\cos ^n \theta$ then $\bigg(\large\frac{dy}{dx}\bigg)^2=$
jeemain
math
class12
ch9
differential-equations
linear-differential-equations
q6
difficult
asked
Jan 31, 2014
by
meena.p
1
answer
If $x= \cos^{-1} \bigg( \large\frac{1}{\sqrt {1+t^2}}\bigg) $ and $\; y= \sin ^{-1} \bigg( \large\frac{1}{\sqrt {1+t^2}}\bigg) $ then $\large\frac{dy}{dx}$
jeemain
math
class12
ch9
differential-equations
solving-using-separation-of-variables
q5
medium
asked
Jan 31, 2014
by
meena.p
1
answer
If $x^2+y^2=t-\large\frac{1}{t} ,$$x^4+y^4 =t^2+\large\frac{1}{t^2}$ then $\large\frac{dy}{dx}$
jeemain
math
class12
ch9
differential-equations
ordinary-differential-equations
q4
medium
asked
Jan 31, 2014
by
meena.p
1
answer
If $\phi (x) =f(x) g(x),$ where $f'(x) g'(x) =c$ and $ \large\frac {\phi ''}{\phi} =\frac {f''}{f} +\frac{g''}{g}+\frac{Kc}{fg}$ then value of K.
jeemain
math
class12
ch9
differential-equations
homogeneous-differential-equations
q3
medium
asked
Jan 31, 2014
by
meena.p
1
answer
Assertion : For the following equation degree $\large\frac{d^4}{dx^4} $$ +\sin \bigg ( \large\frac{d^2y}{dx^2}\bigg)=0$ Reason : Order of DE is the order of highest differentiate coefficient occurring in the equation
jeemain
math
class12
ch7
differential-equations
degree-of-a-differential-equation
q2
difficult
asked
Jan 31, 2014
by
meena.p
1
answer
Solution of differential equation: $X^2= 1+\large\frac{1}{2} \bigg( \large\frac{x}{y}\bigg)^{-1} \frac{dy}{dx} + \large\frac{\bigg(\Large\frac{x}{y}\bigg)^{-2} \bigg(\Large\frac{dy}{dx}\bigg)^{2}}{4 \times 2 \times 1}+ \large\frac{\bigg(\Large\frac{x}{y}\bigg)^{-3} \bigg(\Large\frac{dy}{dx}\bigg)^{3}}{8 \times 3 \times 2 \times 1}+ \large\frac{\bigg(\Large\frac{x}{y}\bigg)^{-4} \bigg(\Large\frac{dy}{dx}\bigg)^{4}}{16 \times 4 \times 3 \times 2 \times 1}+..........$
jeemain
math
class12
unit9
differential-equations
solving-using-separation-of-variables
q1
difficult
asked
Jan 31, 2014
by
meena.p
1
answer
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