Recent questions tagged p375

Find the area under the given curves and given lines: $ (ii)\:y = x^4, x = 1, x = 5 \: and\: x - axis$

asked Aug 16, 2013 by sreemathi.v

1 answer

sketch the graph of y=|x+3| and evaluate $\int_{-6}^0|x+3| dx.$

asked Jan 21, 2013 by sreemathi.v

1 answer

Sketch the graph of y=| x+3 | and evaluate$\Large \int\limits_{-6}^0\normalsize| x+3 |dx$

asked Dec 17, 2012 by sreemathi.v

1 answer

Find the area under the given curves and given lines: $ (i) \: y = x^2, x = 1, x = 2 \: and\: x - axis$

asked Dec 4, 2012 by thanvigandhi_1

1 answer

Find the area between the curves $y = x$ and $y = x^2.$

asked Dec 4, 2012 by thanvigandhi_1

2 answers

Find the area of the region lying in the first quadrant and bounded by $y = 4x^2, x = 0, y = 1$ and $y = 4$.

asked Dec 4, 2012 by thanvigandhi_1

1 answer

Find the area bounded by the curve $(y = \sin\; x) $ between $ (x = 0) $ and $(x = 2π).$

asked Dec 4, 2012 by thanvigandhi_1

1 answer

Find the area enclosed between the parabola $y^2 = 4ax$ and the line $y = mx.$

asked Dec 4, 2012 by thanvigandhi_1

1 answer

Find the area enclosed by the parabola $4y = 3x^2$ and the line $2y = 3x + 12.$

asked Dec 4, 2012 by thanvigandhi_1

1 answer

Find the area of the smaller region bounded by the ellipse $ \frac{\large x^2}{\large 9} + \frac{\large y^2}{\large 4} =1$ and the line $ \frac{\large x}{\large 3}+ \frac{\large y}{\large 2}= 1$

asked Dec 4, 2012 by thanvigandhi_1

1 answer

Find the area of the smaller region bounded by the ellipse $\Large { \frac{ x^2}{ a^2}}+\Large { \frac{ y^2}{ b^2}} =\normalsize 1$ and the line $\Large { \frac{ x}{ a}}+\Large { \frac{y}{ b}} =\normalsize1$

asked Dec 4, 2012 by thanvigandhi_1

1 answer

Find the area of the region enclosed by the parabola $x^2 = y$, the line $y = x + 2$ and the $x$ - axis.

asked Dec 4, 2012 by thanvigandhi_1

1 answer

Using the method of integration find the area bounded by the curve I x I + I y I =1 . [Hint: The required region is bounded by lines $x + y = 1, x - y = 1, -x + y = 1$ and $ -x -y = 1$].

asked Dec 4, 2012 by thanvigandhi_1

1 answer

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Find the area under the given curves and given lines: $ (ii)\:y = x^4, x = 1, x = 5 \: and\: x - axis$

sketch the graph of y=|x+3| and evaluate $\int_{-6}^0|x+3| dx.$

Sketch the graph of y=| x+3 | and evaluate$\Large \int\limits_{-6}^0\normalsize| x+3 |dx$

Find the area under the given curves and given lines: $ (i) \: y = x^2, x = 1, x = 2 \: and\: x - axis$

Find the area between the curves \(y = x\) and \(y = x^2.\)

Find the area of the region lying in the first quadrant and bounded by $y = 4x^2, x = 0, y = 1$ and $y = 4$.

Find the area bounded by the curve $(y = \sin\; x) $ between $ (x = 0) $ and $(x = 2π).$

Find the area enclosed between the parabola \(y^2 = 4ax\) and the line \(y = mx.\)

Find the area enclosed by the parabola \(4y = 3x^2\) and the line \(2y = 3x + 12.\)

Find the area of the smaller region bounded by the ellipse \( \frac{\large x^2}{\large 9} + \frac{\large y^2}{\large 4} =1\) and the line \( \frac{\large x}{\large 3}+ \frac{\large y}{\large 2}= 1\)

Find the area of the smaller region bounded by the ellipse \(\Large { \frac{ x^2}{ a^2}}+\Large { \frac{ y^2}{ b^2}} =\normalsize 1\) and the line \(\Large { \frac{ x}{ a}}+\Large { \frac{y}{ b}} =\normalsize1\)

Find the area of the region enclosed by the parabola \(x^2 = y\), the line \(y = x + 2\) and the \(x\) - axis.

Using the method of integration find the area bounded by the curve I x I + I y I =1 . [Hint: The required region is bounded by lines \(x + y = 1, x - y = 1, -x + y = 1\) and \( -x -y = 1\)].