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(chatquestion)...3.78. Near the point A (Fig. 3.10) lying on the boundary between glass and vacuum the electric field strength in vacuum is equal to 10.0 V/m, the angle between the vector E, and the normal E, n of the boundary line being equal to a, = 30°. Find the field streng E in glass near the point A, the angle a between the vector E and a as well as the surface density of the bound charges at the point A. 319. Near the nlane e %3D Eo Fig. 3.10.
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telegram-2400
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Jun 4, 2020
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balaji.thirumalai
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