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(chatquestion)...Illustration 11. Atom A is every element of FCC, atom B is present at every Octahedral void, atom C is prese 3 x2R= 2 25% of Tetrahedral void. Find out the possible molecular formula of the compound ? Atom A is every element of FCC = 4 atoms of A Solution. 3x 2R Atom B is present at every octahedral void = 4 atoms of B 2R B-4 noot Ay ByC2 Atom C is present at 25% of tetrahedral void = 8x- 25 2 atoms of C %3D 100 So, the possible molecular formula is A, B, C, = A, B, C.

asked Jan 25, 2020 by balaji.thirumalai

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