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Recent questions tagged telegram-54099

(chatquestion)...WB=2g, K, =4.9K kg mol-, WA=25g, AT; =1.62K W3 1000 м, WA AT;=K÷x- 4.9x2x1000 M3 =241.98g mol 1.62x25 2C,Н,СООН (С Н.СООН), if 'x' is degree of association then we would have (1-x) mol of Benzoic acid left undissociated and corresponding x/2 as associated moles of Benzoic acid at equilibrium. Therefore, total number of moles of particles at equilibrium is 1-x+=1- 122 Normal molecular mass Abnormal molecular mass 241.98 122 х =1- 2 241.98 122 241.98 –122 х =1 241.98 241.98 239.96 = 0.992 = 99.2% 241.98 Therefore degree of association of Benzoic acid is Benzene is 99.2 %

asked Feb 1, 2020 by balaji.thirumalai

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