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Answers posted by sreemathi.v

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answered Feb 6, 2013
Toolbox: (i)If the rational is improper in nature we can divide and separate the terms to ...
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answered Feb 6, 2013
Toolbox: $(i)\;$Form of the rational function\[\frac{px+q}{(x+a)(x+b)(x+c)}\] $\;$Fo...
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answered Feb 6, 2013
Toolbox: $(i)\;$Form of the rational function\[\frac{px+q}{(x-a)(x-b)(x-c)}\] $\;$Form of the ...
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answered Feb 6, 2013
Toolbox: $(i)\;$Form of the rational function\[\frac{px+q}{(x-a)^2(x-b)}\] $\;$Form ...
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answered Feb 6, 2013
Toolbox: $(i)\;$Form of the rational function\[\frac{px+q}{(x-a)^2(x-b)}\] $\;$Form ...
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answered Feb 5, 2013
Toolbox: $(i)\;$Form of the rational function\[\frac{px+q}{(x+a)(x^2+b)}\] $\;$Form ...
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answered Feb 5, 2013
Toolbox: $(i)\;$Form of the rational function\[\frac{px+q}{(x+a)(x+b)}\] $\;$Form of...
0 votes
answered Feb 5, 2013
Toolbox: $(i)\;$Form of the rational function\[\frac{px+q}{(x-a)(x-b)(x-c)},a\neq b\neq c\...
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answered Feb 5, 2013
Toolbox: $(i)\;$Form of the rational function\[\frac{px+q}{(x-a)(x-b)(x-c)},a\neq b\neq c\...
0 votes
answered Feb 5, 2013
Toolbox: $(i)\;$Form of the rational function\[\frac{px+q}{(x-a)(x-b)},a\neq b\] $(i...
0 votes
answered Feb 5, 2013
Toolbox: $(i)\;$Form of the rational function\[\frac{px+q}{(x-a)(x-b)},a\neq b\] $(i...
0 votes
answered Feb 5, 2013
Toolbox: $\int\frac{dx}{a^2-x^2}=\sin^{-1}\big(\frac{x}{a}\big)+c.$ Given $I=\int\...
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answered Feb 5, 2013
Toolbox: $\int\frac{dx}{x^2+a^2}=\frac{1}{a}\tan^{-1}\big(\frac{x}{a}\big)+c.$ Giv...
0 votes
answered Feb 5, 2013
Toolbox: $(i)\int\frac{(px+q)}{\sqrt{ax^2+bx+c}}dx.$,where p,q,a,b,c are constants,we are ...
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answered Feb 5, 2013
Toolbox: $(i)\int\frac{(px+q)}{\sqrt{ax^2+bx+c}}dx.$,where p,q,a,b,c are constants,we are ...
0 votes
answered Feb 5, 2013
Toolbox: $(i)\int\frac{(px+q)}{\sqrt{ax^2+bx+c}}dx.$,where p,q,a,b,c are constants,we are ...
0 votes
answered Feb 4, 2013
Toolbox: $(i)\int\frac{(px+q)}{\sqrt{ax^2+bx+c}}dx.$,where p,q,a,b,c are constants,we are ...
0 votes
answered Feb 4, 2013
Toolbox: $(i)\int\frac{(px+q)}{\sqrt{ax^2+bx+c}}dx.$,where p,q,a,b,c are constants,we are ...
0 votes
answered Feb 4, 2013
Toolbox: $(i)\int\frac{(px+q)}{\sqrt{ax^2+bx+c}}dx.$,where p,q,a,b,c are constants,we are ...
0 votes
answered Feb 4, 2013
Toolbox: $(i)\int\frac{(px+q)}{\sqrt{ax^2+bx+c}}dx.$,where p,q,a,b,c are constants,we are ...
0 votes
answered Feb 4, 2013
Toolbox: $\int\frac{(px+q)}{\sqrt{ax^2+bx+c}}dx.$,where p,q,a,b,c are constants,we are to ...
0 votes
answered Feb 4, 2013
Toolbox: $\int\frac{dx}{\sqrt{x^2-a^2}}=log\mid x+\sqrt{x^2-a^2}\mid+c.$ Given:$I=...
0 votes
answered Feb 4, 2013
Toolbox: $\int\frac{dx}{\sqrt{a^2-x^2}}=\sin^{-1}\big(\frac{x}{a}\big)+c.$ Given:$...
0 votes
answered Feb 4, 2013
Toolbox: $\int\frac{dx}{\sqrt{x^2-a^2}}=log\mid x+\sqrt{x^2-a^2}\mid+c.$ Given:$I=...
0 votes
answered Feb 4, 2013
Toolbox: $\int\frac{dx}{\sqrt{a^2-x^2}}=\sin^{-1}\big(\frac{x}{a}\big)+c.$ Given $...
0 votes
answered Feb 4, 2013
Toolbox: $\int\frac{dx}{x^2+a^2}=\frac{1}{a}\tan^{-1}\big(\frac{x}{a}\big)+c.$ Giv...
0 votes
answered Feb 4, 2013
Toolbox: $\int\frac{dx}{\sqrt{x^2+a^2}}=\int log\mid x+\sqrt{x^2+a^2}\mid+c.$ Give...
0 votes
answered Feb 4, 2013
Toolbox: $\int\frac{dx}{\sqrt{x^2+a^2}}=\int log\mid x+\sqrt{x^2+a^2}\mid+c.$ Give...
0 votes
answered Feb 4, 2013
Toolbox: $\int\frac{dx}{\sqrt{x^2+a^2}}=\int log\mid x+\sqrt{x^2+a^2}\mid+c.$ Give...
0 votes
answered Feb 4, 2013
Toolbox: $\int\frac{dx}{\sqrt{x^2-a^2}}=\int log\mid x+\sqrt{x^2-a^2}\mid+c.$ Give...
0 votes
answered Feb 4, 2013
Toolbox: $\int\frac{dx}{\sqrt{a^2+x^2}}=\frac{1}{2a}log\mid\frac{a+x}{a-x}\mid+c.$ ...
0 votes
answered Feb 4, 2013
Toolbox: $\int\frac{dx}{\sqrt{a^2+x^2}}=\frac{1}{a}\tan^{-1}\big(\frac{x}{a}\big)+c.$ ...
0 votes
answered Feb 4, 2013
Toolbox: $\int\frac{dx}{\sqrt{a^2+x^2}}=\sin^{-1}\big(\frac{x}{a}\big)+c.$ Given:$...
0 votes
answered Feb 4, 2013
Toolbox: $\int\frac{dx}{\sqrt{a^2+x^2}}=log\mid x+\sqrt{x^2+a^2}\mid+c.$ Given:$I=...
0 votes
answered Feb 4, 2013
Toolbox: $\int\frac{dx}{\sqrt{a^2+x^2}}=log\mid x+\sqrt{x^2+a^2}\mid+c.$ Given:$I=...
0 votes
answered Feb 3, 2013
Toolbox: $(i)\;\int \frac{dx}{x^2+1}=\tan^{-1}x+c.$ Given $I=\int\frac{3x^2}{x^6+1...
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answered Feb 3, 2013
Toolbox: $(i)\;\int e^{-x}=e^{-x}+c.$ $(ii)\;\int\sec^2xdx=\tan x+c.$ Given ...
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answered Feb 3, 2013
Toolbox: $(i)\;\int \sec^2xdx=\tan x+c.$ $(ii)\;\int cosec^2xdx=-\cot x+c.$ ...
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answered Feb 3, 2013
Toolbox: $(i)\;\sin(A+B)=\sin A\cos B+\cos A\sin B.$ $(ii)\;\int\tan xdx=-log|\cos x...
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answered Feb 3, 2013
Toolbox: $(i)\;\int\frac{1}{\sqrt{1-x^2}dx}=\sin^{-1}x+c.$ $(ii)\;$Method of substit...
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answered Feb 3, 2013
Toolbox: $(i)\;\sin2x=2\sin x\cos x.$ $(ii)\;\int\frac{1}{x}dx=log x+c.$ $(iii...
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answered Feb 3, 2013
Toolbox: $(i)\;\sin^2x+\cos^2x=1.$ $(ii)\;Method\;of\;substitution.$ Let f(x)=...
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answered Feb 3, 2013
Toolbox: $(i)\cos2x=1-2\sin^2 x+c.$ $(ii)\;\int \sec^2xdx=\tan x+c$. Given $...
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answered Feb 3, 2013
Toolbox: $(i)\;\int\sec x\tan xdx=\sec x+c.$ $(ii)\;\int \cot xcosec xdx=-cosec x+c$...
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answered Jan 31, 2013
Toolbox: $(i)\tan^2x=\sec^2x-1$ $(ii)\int \sec^2xdx=\tan x+c.$ Given $I=\int...
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answered Jan 31, 2013
Toolbox: $\tan^2x=\sec^2x-1.$ $(ii)\int \sec^2xdx=\tan x+c.$ Given $I=\int\t...
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answered Jan 31, 2013
Toolbox: $(i)\sin^2x+\cos^2x=1.$ $(ii)\sin2x=2\sin x\cos x.$ $(iii)method\;of\...
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answered Jan 31, 2013
Toolbox: $(i)\cos C-\cos D=-2\sin\frac{(C+D)}{2}\sin\frac{(C-D)}{2}.$ $(ii)\sin x=2\...
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answered Jan 31, 2013
Toolbox: $(i)\sin2x=2\sin x\cos x.$ $\cos x=2\cos^2\frac{x}{2}-1.$ $(iii)\sin ...
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answered Jan 31, 2013
Toolbox: $(i)\sin^2x=\frac{(1-\cos 2x)}{2}.$ $(ii)\int\cos ^2xdx=\frac{(1+\cos2 x)}{...
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