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Recent questions tagged differential-equations
Questions
General solution of differential equations: $e^y dx+(xe^y-2y)dy=0$
jeemain
math
class12
ch9
differential-equations
solving-using-separation-of-variables
q9
medium
asked
Feb 3, 2014
by
meena.p
1
answer
General solution of differential equation: $\large\frac{xdy}{x^2+y^2} $$+\bigg(1- \large\frac{y}{x^2+y^2} \bigg)$$dx=0$ is
jeemain
math
class12
ch9
differential-equations
solving-using-separation-of-variables
q8
difficult
asked
Feb 3, 2014
by
meena.p
1
answer
General solution of $(2x^3-xy^2)dx+(2y^3-x^2y)dy=0$ is
jeemain
math
class12
ch9
differential-equations
ordinary-differential-equations
q7
difficult
asked
Feb 3, 2014
by
meena.p
1
answer
If $x= \sec \theta -\cos \theta $ and $y=\sec^n \theta -\cos ^n \theta$ then $\bigg(\large\frac{dy}{dx}\bigg)^2=$
jeemain
math
class12
ch9
differential-equations
linear-differential-equations
q6
difficult
asked
Jan 31, 2014
by
meena.p
1
answer
If $x= \cos^{-1} \bigg( \large\frac{1}{\sqrt {1+t^2}}\bigg) $ and $\; y= \sin ^{-1} \bigg( \large\frac{1}{\sqrt {1+t^2}}\bigg) $ then $\large\frac{dy}{dx}$
jeemain
math
class12
ch9
differential-equations
solving-using-separation-of-variables
q5
medium
asked
Jan 31, 2014
by
meena.p
1
answer
If $x^2+y^2=t-\large\frac{1}{t} ,$$x^4+y^4 =t^2+\large\frac{1}{t^2}$ then $\large\frac{dy}{dx}$
jeemain
math
class12
ch9
differential-equations
ordinary-differential-equations
q4
medium
asked
Jan 31, 2014
by
meena.p
1
answer
If $\phi (x) =f(x) g(x),$ where $f'(x) g'(x) =c$ and $ \large\frac {\phi ''}{\phi} =\frac {f''}{f} +\frac{g''}{g}+\frac{Kc}{fg}$ then value of K.
jeemain
math
class12
ch9
differential-equations
homogeneous-differential-equations
q3
medium
asked
Jan 31, 2014
by
meena.p
1
answer
Assertion : For the following equation degree $\large\frac{d^4}{dx^4} $$ +\sin \bigg ( \large\frac{d^2y}{dx^2}\bigg)=0$ Reason : Order of DE is the order of highest differentiate coefficient occurring in the equation
jeemain
math
class12
ch7
differential-equations
degree-of-a-differential-equation
q2
difficult
asked
Jan 31, 2014
by
meena.p
1
answer
Solution of differential equation: $X^2= 1+\large\frac{1}{2} \bigg( \large\frac{x}{y}\bigg)^{-1} \frac{dy}{dx} + \large\frac{\bigg(\Large\frac{x}{y}\bigg)^{-2} \bigg(\Large\frac{dy}{dx}\bigg)^{2}}{4 \times 2 \times 1}+ \large\frac{\bigg(\Large\frac{x}{y}\bigg)^{-3} \bigg(\Large\frac{dy}{dx}\bigg)^{3}}{8 \times 3 \times 2 \times 1}+ \large\frac{\bigg(\Large\frac{x}{y}\bigg)^{-4} \bigg(\Large\frac{dy}{dx}\bigg)^{4}}{16 \times 4 \times 3 \times 2 \times 1}+..........$
jeemain
math
class12
unit9
differential-equations
solving-using-separation-of-variables
q1
difficult
asked
Jan 31, 2014
by
meena.p
1
answer
The rate at which the population of a city increases at any time is propotional to the population at that time. If there were $1,30,000$ people in the city in $1960 $ and $1,60,000$ in $1990$ what population may be anticipated in $2020$.$[\log_{e}(\large\frac{16}{13})=$$.2070;$$e^{.42}=1.52]$
math
tnstate
class12
bookproblem
ch8
sec-1
exercise8-6
p155
q4
medium
jeemain
differential-equations
asked
Apr 17, 2013
by
poojasapani_1
1
answer
Solve the following $(x+y)^2 \large\frac{dy}{dx}$=$1$
tnstate
class12
math
bookproblem
q8
sec-1
exercise8-2
p133
q7
jeemain
differential-equations
modelpaper
oct-2008
asked
Apr 15, 2013
by
poojasapani_1
1
answer
The curve for which the slope of the tangent at any point is equal to the ratio of the abscissa to the ordinate of the point is
class12
cbse
ch9
sec-a
q62
p199
objective
exemplar
easy
jeemain
differential-equations
math
asked
Jan 19, 2013
by
sreemathi.v
1
answer
If $y=e^{-x}(A\cos x+B\sin x)$, then $y$ is a solution of
cbse
class12
ch9
differential-equations
sec-a
q37
p195
objective
exemplar
difficult
math
asked
Jan 18, 2013
by
sreemathi.v
1
answer
Form the differential equation of all circles which pass through origin and whose centers lie on y-axis as shown below:
cbse
class12
ch9
sec-b
q14
p194
short-answer
exemplar
math
difficult
jeemain
differential-equations
asked
Jan 18, 2013
by
sreemathi.v
1
answer
If $y=y(x)$ satisfies $x\cos y + y\cos x = \pi$, then find $y''(0)$:
cbse
class12
ch5
math
differential-equations
additionalproblem
jeemain
difficult
sec-b
asked
Jan 3, 2013
by
sreemathi.v
1
answer
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