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Answers posted by meena.p

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answered Jul 31, 2018
Solution : In the equation of state of an ideal gas PV = nRT, the value of the universal gas constan...
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answered Jul 31, 2018
Solution : : PV=constPV=const$P_1V_1=P_2V_2$$P_2=P_1V_1/V_2$$\qquad=P_1V_1/1.1V_1$$\qquad= 0.9\;P_1$...
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answered Jul 31, 2018
Solution : If a gas expands at constant temperature, then pressure of the gas decrease and number of...
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answered Jul 31, 2018
Solution : Given, P = 720 / 760 atm, T = 295K, w = 4g and m = 4 for He PV = w / M RT = 720 / 760...
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answered Jul 31, 2018
Solution : Given $V_1= 1\;litre$$P_1=1\;atm$$V_2=?$$P_2=750/760\;atm$Using$P_1V_1=P_2V_2$$1 \times 1...
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answered Jul 31, 2018
Solution : The amount of energy needed to change a substance from a solid phase to a liquid phase is...
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answered Jul 31, 2018
Answer : p=152" role="presentation" style="position: relative;">p=152p=152p=\large\frac{15}{2};q=...
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answered Jul 31, 2018
Solution : $x^2-6x+7=0$$(x-7)(x+1)=0$=> $\alpha=7$ and $\beta=-1$$\therefore \large\frac{1}{\alph...
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answered Jul 31, 2018
Solution : $b^2-4ac= 16-4 \times 1 \times m=0$=> $16=4m$=> $m= 4$
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answered Jul 31, 2018
Solution : $(3x+1)^2=-2x$=> $9x^2+6x-1-2x=0$=> $9x^2+4x+1=0$=> $b^2-4ac=16-4 \times 9 \time...
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answered Jul 31, 2018
Solution : $\large\frac{x+3}{1-x}=\frac{-9}{x}$=> $x(x+3)=-9(1-x)$=> $x^2+3x=-9+9x$=> $(x-3...
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answered Jul 31, 2018
Solution : $6x^2+5x-6=0$$6x^2+9x-4x-6=0$$3x(2x+3)-2(2x+3)=0$=> $(3x-2)(2x+3)=0$$3x-2=0$When $2x+3...
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answered Jul 31, 2018
Solution : $\large\frac{4(2x^2+7x+3)}{8x+4}=\frac{4(2x^2+7x+3)}{4(2x+1)}$$2x^2+7x+3=2x^2+6x+x+3$$\qq...
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answered Jul 30, 2018
Solution : Put $x^2=a$$\therefore a^2+3a-10=0$Using the quadratic formula , $\large\frac{-b \pm \sqr...
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answered Jul 30, 2018
Solution : $2(l+w)=80$=> $l(40-l)=400$=> $4=l-l^2=400$=> $l^2-20l-20l+400=0$=> $l^2=20l-...
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answered Jul 30, 2018
Solution : $2x^2-6x+3$The discriminate value $b^2-4ac$ is $6^2-4 \times 2 \times 3$$\qquad=36-24$Hen...
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answered Jul 30, 2018
Solution : $x(x+3)=54$$x^2+3x-54=0$On factoring $(x+9)(x-6)=0$Since we cannot consider $x=-9$ let us...
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answered Jul 30, 2018
Solution : To make the fraction undefined $9x^2-1=0$=> $9x^2=1$=> $x^2=\large\frac{1}{9}$=>...
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answered Jul 30, 2018
Solution : $x^2=3x-2$=> $x^2-3x+2=0$=> $(x-2)(x-1)=0$=> $x=2,1$
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answered Jul 30, 2018
Solution : $3t^2+4t+1=0$=> $3t^2+3t+t+1=0$=> $3t(t+1)+1(t+1)=0$=> $(3t+1)(t+1)=0$=> $3t=...
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answered Jul 30, 2018
Solution : $x^2-9x+20=(x-4)(x-5)$$x^2-x-12=(x-4)(x+3)$$\large\frac{x^2-9x+20}{x^2-x-12}=\frac{(x-4)(...
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answered Jul 30, 2018
Solution : $3n^2-2n=-1+2n^2$=> $n^2-2n+1=0$=> $(n-1)^2=0$=> $n=1$
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answered Jul 30, 2018
Solution : $4t^2+21t+5=4t^2+20t+t+5$=4t(t+5)+1(t+5)" role="presentation" style="position: relative;"...
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answered Jul 30, 2018
Since Magnetic moment = n(n+2)=√n(n+2)= 4.9$\therefore$ n= 4(where n is no. of unpaired electron)Thu
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answered Jul 30, 2018
Solution : $E_n= \large\frac{E_1}{n^2}$$E_2= \large\frac{E_1}{(2)^2}$$=-328\;kJ \;mol^{-}$$E_1=-328 ...
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answered Jul 30, 2018
Solution : A 150 watt bulb emits 150 J of the energy The energy emitted by the bulb as light$\qquad=...
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answered Jul 30, 2018
Solution : Charge carried by one electron $=1.6022 \times 10^{-19}\;C$$\therefore $ Electrons presen...
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answered Jul 27, 2018
Solution : (c)spin quantum number
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answered Jul 27, 2018
Solution : $\lambda = \large\frac{h}{mv}$$\qquad= \large\frac{6.626 \times 10^{-34} \;kg\;m^2s^{-1}}...
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answered Jul 27, 2018
Solution : Mass of the electron $ m=9.1 \times 10^{-31}\;kg$$K.E=\large\frac{1}{2}$$mv^2=5 \times 10...
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answered Jul 27, 2018
Solution : $E=N_0hv =N_0h \large\frac{c}{\lambda}$$\qquad= \large\frac{6.02 \times 10^{23} \times 6....
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answered Jul 27, 2018
Solution : The shortest wavelength transition corresponds to $n_2 \infty$ to $n_1=2$ transition . $\...
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answered Jul 27, 2018
Solution : $\large\frac{1}{\lambda}$$=109678 \bigg[\large\frac{1}{n_1^2}-\frac{1}{n_2^2}\bigg]$$\qqu...
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answered Jul 26, 2018
Solution : n represent the main energy level and f represents the subshellIf $n=4$ and $l=3$ the sub...
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answered Jul 26, 2018
Solution : $ns \to (n-s)f \to (n-1)d \to np$$6s \to 4f \to 5d \to 6p$ for $n=6$
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answered Jul 26, 2018
Solution : Number of atomic orbital is an orbit is given by $=n^2=4^2=16$The number of atomic orbita...
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answered Jul 26, 2018
Solution : $_{37}Rb=_{36} [Kr]5s^1$Its valance electron is $5s^1$So, $n= 5,l=0$$m=0$$s= +\large\frac...
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answered Jul 26, 2018
Solution : $E_1-E_2=1312 \times Z^2 \bigg(\large\frac{1}{1^2}-\frac{1}{2^2}\bigg)$$=1312 \times Z^2\...
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answered Jul 26, 2018
Solution : $y=3(x^2+10x+25)+12$=> $y= 3x^2+30x+75+12$=> $y=3x^2+30x+87$
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answered Jul 26, 2018
Solution : $x^2+8x+12=0$$x= \large\frac{-b \pm \sqrt{b^2-4ac}}{2a}$$\quad= \large\frac{-8 \pm \sqrt{...
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answered Jul 26, 2018
Solution : $(-2)^2-2p(-2)+p^2=0$$4+4p+p^2=0$=> $(P+2)^2=0$=> $P=-2$
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answered Jul 26, 2018
Solution : $ y = 0 $$(2x-3)(x+5)=0$if $2x-3=0$ => $ x= \large\frac{3}{2}$if $x+5=0$ => $ x= -5...
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answered Jul 26, 2018
Solution : $x^2-x-30=0$=> $x^2-6x+5x+30=0$=> $x(x-6)+5(x-6)=0$=> $(x+5)(x-6)=0$When $x=-5,x...
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answered Jul 26, 2018
Solution : $2x-5 \sqrt x+9=16$Put $\sqrt{x}=a$ $x=a^2$Hence the equation can be written as=> $2a^...
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answered Jul 26, 2018
Solution : $\large\frac{1}{4} $$(4x^2-8x-p)=132$=> $x^2-2x- \large\frac{p}{4}$$=132$=> $x^2-2x...
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answered Jul 25, 2018
Solution : $Ni^{3+}(28)=[Ar]3d^7$$Mn^{3+}(25)=[Ar]3d^4$$Fe^{3+}(26)=[Ar]3d^5$$Co^{3+}(27)=[Ar]3d^6$
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answered Jul 25, 2018
Solution : Deuterium an isotope of hydrogen , is $_1 H^{2}$Thus it contains 1 proton and $1(2-1)$ ne...
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answered Jul 25, 2018
Solution : According to be Brogile equation $\lambda= \large\frac{h}{mv}$Mass of electron $=9.1 \tim...
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