Recent questions tagged p169

The value of $\large\int\limits_{-\pi}^\pi$$\sin^3x\cos^2x dx$ is___________.

asked Jan 15, 2013 by sreemathi.v

1 answer

$\Large\int\frac{\sin x}{3+4\cos^2x}$$dx$=___________.

asked Jan 15, 2013 by sreemathi.v

1 answer

If $\Large \int\frac{1}{1+4x^2}$$dx=\large\frac{\pi}{8},$then a=____________.

asked Jan 15, 2013 by sreemathi.v

1 answer

$\int\Large{\frac{x+3}{(x+4)^2}}\normalsize e^xdx$=___________.

asked Jan 15, 2013 by sreemathi.v

1 answer

$\int\limits_0^{\Large\frac{\pi}{2}}\cos x\;e^{\sin x} dx$ is equal to ____________.

asked Jan 15, 2013 by sreemathi.v

1 answer

$\Large \int\limits_0^\frac{\pi}{2}\normalsize \sqrt {1-\sin2x}\;dx$ is equal to $(A)\;0\quad(B)\;2\quad(C)\;1\quad(D)\;-1$

asked Jan 15, 2013 by sreemathi.v

1 answer

$\Large \int\limits_\frac{-\pi}{4}^\frac{\pi}{4}\frac{dx}{1+\cos2x}$ is equal to $(A)\;1\quad(B)\;2\quad(C)\;3\quad(D)\;4$

asked Jan 15, 2013 by sreemathi.v

1 answer

Find $\large \frac {dy}{dx} $ in the following: $ y = sec^{-1} \left(\large\frac{1}{2x^2 - 1}\right), 0 < x < \; { \frac{1}{\sqrt2} } \\ $

asked Nov 16, 2012 by thanvigandhi_1

1 answer

Find $\large \frac {dy}{dx} $ in the following: $y = \sin^{-1} \big( 2x \sqrt{1 -x^2} \big), -\;{ \frac{1}{\sqrt2} }\;< x < \;{\frac{1}{\sqrt2} }\\ $

asked Nov 16, 2012 by thanvigandhi_1

1 answer

Find $ \large\frac {dy}{dx} $ in the following: $ y = cos^{-1} \left(\large\frac{2x}{1 + x^2}\right), -1 < x < 1 $

asked Nov 15, 2012 by thanvigandhi_1

1 answer

Find $ \frac {dy}{dx} $ in the following:$ y = sin^{-1} \left(\frac{1 - x^2}{1 + x^2}\right), 0 < x < 1 $

asked Nov 15, 2012 by thanvigandhi_1

1 answer

Find $ \frac {dy}{dx} $ in the following: $y = cos^{-1} \left(\frac{1 - x^2}{1 + x^2}\right), 0 < x < 1 $

asked Nov 15, 2012 by thanvigandhi_1

1 answer

Find $ \frac {dy}{dx}$ in the following: $y = tan^{-1} \left(\frac{3x - x^3}{1 - 3x^2}\right), - \; { \frac{1}{\sqrt3} } < x < \;{\frac{1}{\sqrt3} }\\ $

asked Nov 15, 2012 by thanvigandhi_1

1 answer

Find $ \frac {dy}{dx} $ in the following: $ y = sin^{-1} \left(\frac{2x}{1 + x^2}\right) $

asked Nov 15, 2012 by thanvigandhi_1

1 answer

Find $ \frac {dy}{dx} $ in the following: $ \sin^2x +\cos^2y = 1 $

asked Nov 11, 2012 by thanvigandhi_1

1 answer

Find $ \frac {dy}{dx} $ in the following: $ sin^2y + cos \: xy = k $

asked Nov 11, 2012 by thanvigandhi_1

1 answer

Find $ \frac {dy}{dx} $ in the following: $ x^3 +x^2y + xy^2 +y^3 = 81 $

asked Nov 11, 2012 by thanvigandhi_1

1 answer

Find $ \frac {dy}{dx} $ in the following: $ x^2 +xy + y^2 = 100 $

asked Nov 11, 2012 by thanvigandhi_1

1 answer

Find $ \frac {dy}{dx} $ in the following: $ xy +y^2 = tan \: x + y $

asked Nov 11, 2012 by thanvigandhi_1

1 answer

Find $\frac {dy}{dx}$ in the following: $ax +by^2 = cos \: y$

asked Nov 11, 2012 by thanvigandhi_1

1 answer

Find $\frac {dy}{dx}$ in the following: $2x +3y = sin \: y$

asked Nov 11, 2012 by thanvigandhi_1

1 answer

Ask Questions, Get Answers

The value of $\large\int\limits_{-\pi}^\pi$$\sin^3x\cos^2x dx$ is___________.

$\Large\int\frac{\sin x}{3+4\cos^2x}$$dx$=___________.

If $\Large \int\frac{1}{1+4x^2}$$dx=\large\frac{\pi}{8},$then a=____________.

$\int\Large{\frac{x+3}{(x+4)^2}}\normalsize e^xdx$=___________.

$\int\limits_0^{\Large\frac{\pi}{2}}\cos x\;e^{\sin x} dx$ is equal to ____________.

$\Large \int\limits_0^\frac{\pi}{2}\normalsize \sqrt {1-\sin2x}\;dx$ is equal to $(A)\;0\quad(B)\;2\quad(C)\;1\quad(D)\;-1$

$\Large \int\limits_\frac{-\pi}{4}^\frac{\pi}{4}\frac{dx}{1+\cos2x}$ is equal to $(A)\;1\quad(B)\;2\quad(C)\;3\quad(D)\;4$

Find $\large \frac {dy}{dx} $ in the following: $ y = sec^{-1} \left(\large\frac{1}{2x^2 - 1}\right), 0 < x < \; { \frac{1}{\sqrt2} } \\ $

Find $\large \frac {dy}{dx} $ in the following: $y = \sin^{-1} \big( 2x \sqrt{1 -x^2} \big), -\;{ \frac{1}{\sqrt2} }\;< x < \;{\frac{1}{\sqrt2} }\\ $

Find \( \large\frac {dy}{dx} \) in the following: $ y = cos^{-1} \left(\large\frac{2x}{1 + x^2}\right), -1 < x < 1 $

Find $ \frac {dy}{dx} $ in the following:$ y = sin^{-1} \left(\frac{1 - x^2}{1 + x^2}\right), 0 < x < 1 $

Find \( \frac {dy}{dx} \) in the following: $y = cos^{-1} \left(\frac{1 - x^2}{1 + x^2}\right), 0 < x < 1 $

Find $ \frac {dy}{dx}$ in the following: $y = tan^{-1} \left(\frac{3x - x^3}{1 - 3x^2}\right), - \; { \frac{1}{\sqrt3} } < x < \;{\frac{1}{\sqrt3} }\\ $

Find $ \frac {dy}{dx} $ in the following: $ y = sin^{-1} \left(\frac{2x}{1 + x^2}\right) $

Find $ \frac {dy}{dx} $ in the following: $ \sin^2x +\cos^2y = 1 $

Find \( \frac {dy}{dx} \) in the following: \( sin^2y + cos \: xy = k \)

Find $ \frac {dy}{dx} $ in the following: $ x^3 +x^2y + xy^2 +y^3 = 81 $

Find $ \frac {dy}{dx} $ in the following: $ x^2 +xy + y^2 = 100 $

Find $ \frac {dy}{dx} $ in the following: $ xy +y^2 = tan \: x + y $

Find $\frac {dy}{dx}$ in the following: $ax +by^2 = cos \: y$

Find $\frac {dy}{dx}$ in the following: $2x +3y = sin \: y$