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Answers posted by thanvigandhi_1

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answered Mar 12, 2013
Toolbox: Open the determinent and then differentiate. $ f(x) = 2\: x^3$ $ f ' ...
0 votes
answered Mar 12, 2013
Toolbox: Check $ f $ is continuous and differentiable in $ \bigg[ 0, \large\frac{\pi}{2} \...
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answered Mar 12, 2013
Toolbox: If there is a variable in index then use log before differentiating. $ log\...
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answered Mar 12, 2013
Toolbox: Use chain rule. $ tan^{-1}\large \frac{a+b}{1-ab} = tan^{-1}a+tan^{-1}b$ ...
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answered Mar 11, 2013
Toolbox: For continuity $ LHL = RHL = f(0)$ $ \lim\limits_{x \to 0}\large\frac{tan\:...
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answered Mar 11, 2013
Toolbox: Check $ LHL = RHL = f(2)$ $ [x] = n \: where\: n \leq x\: n+1\: and \: n \i...
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answered Mar 11, 2013
Toolbox:Check whether \( LHL = RHL = f(a)\) at any point \( x = a\)LHL \( \lim\limits_{x \to \overli...
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answered Mar 11, 2013
Toolbox: For continuous at $ x = \pi, LHL = RHL = f(\pi)$ $ LHL\: \lim\limits_{h \...
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answered Mar 11, 2013
Toolbox: For $f(x)$ to be continuous at $ '0' LHL = RHL = f(0)$ $ \lim\limits_{x \to...
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answered Mar 11, 2013
Ans : $ f(x)$ is continuous at all the points in the domain. Take any point $ a \in R$ chec...
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answered Mar 11, 2013
Toolbox: For continuity at '0' LHL = RHL = f(0) $ \lim\limits_{x \to 0} \: \large\fr...
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answered Mar 9, 2013
Toolbox: \( sin^{-1}(x\sqrt{1-y^2}+y\sqrt{1-x^2} )=sin^{-1}x+sin^{-1}y\) Take x as...
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answered Mar 9, 2013
Toolbox: $ sin^{-1} [ x\sqrt{1-y^2}+y\sqrt{1-x^2} ] = sin^{-1}x+sin^{-1}y$ Consider ...
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0 votes
answered Mar 9, 2013
Toolbox: Write $\large \frac{4x}{1+5x^2}=\large\frac{5x-x}{1+5x^2}, \large\frac{2+3x}{3-2x...
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answered Mar 9, 2013
Toolbox:Divide number and then by b cos x $ tan^{-1}\large\frac{x-y}{1+xy}=tan^{-1}x-tan^{-1}y$ ...
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answered Mar 9, 2013
Toolbox: $ sin^{-1} ( x\sqrt{1-y^2}-y\sqrt{1-x^2})=sin^{-1}x-sin^{-1}y$ Take $ x=x\:...
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answered Mar 9, 2013
Toolbox: Put $ x = sin \theta\: and \: y = sin\phi$ Simplify and differentiate after...
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answered Mar 9, 2013
Toolbox: before differentiating eliminate modulus by its definition. $ | cos\: x|=...
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answered Mar 9, 2013
Toolbox: $ tan^{-1}\large\frac{x+y}{1-xy} = tan^{-1}x+tan^{-1}y$ $ y=tan^{-1}\: x^...
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answered Mar 9, 2013
Toolbox: Use chain rule for differentiating y $\large\frac{dy}{dx}=f ' \bigg(\larg...
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answered Mar 9, 2013
Toolbox: When you have any function on the index then use log before differentiating. ...
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answered Mar 9, 2013
Toolbox: $\large \frac{dy}{dx}=\large\frac{\large\frac{dy}{d\theta}}{\large\frac{dx}{d\the...
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answered Mar 9, 2013
Toolbox: Assume $ cos^{-1} \bigg( \large\frac{3cosx-2sinx}{\sqrt{13}} \bigg) = u \: and $ ...
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answered Mar 9, 2013
Toolbox: Use chain rule and differentiate $\large \frac{dy}{dx}=\large\frac{2x}{2\...
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answered Mar 9, 2013
Toolbox: Shift one term to R.H.S square and then differentiate Step 1 $ x \sqr...
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answered Mar 8, 2013
Toolbox: Check whether the function is continuous or not in the given closed interval [ a,...
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answered Mar 8, 2013
Toolbox: As per Rolle's theorem $ f(a)=f(b) \: and \: f'(c) = 0$ $ f(1) = -5...
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answered Mar 8, 2013
Toolbox: If a function is differentiable in an interval it is continuous in that interval....
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answered Mar 8, 2013
Toolbox: M.V.T is Check whether the function is continuous in [ a, b ] and different...
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answered Mar 8, 2013
Toolbox: Check whether the function is continuous or not in the given closed interval [ a,...
0 votes
answered Mar 7, 2013
Toolbox: Drop perpendicular from the point to Y axis and XY plane. Join the foot of ...
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answered Mar 7, 2013
Toolbox: Solve the two equations to get the d.r of both the lines $ d_1, d_2$ Prove ...
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answered Mar 6, 2013
Toolbox:To get distance between a point and line get foot of $ \perp$ of the point on the line and ...
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answered Mar 2, 2013
Toolbox:Take $\sin^{-1}\frac{3}{4}=x$ and proceed$\cos x=2cos^2\frac{x}{2}-1$$\cos x=\sqrt{1-\sin^2x...
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answered Mar 2, 2013
Toolbox:\( cosA\: cosB+sinA\: sinB=cos(A-B)\)\(sinx=\sqrt{1-cos^2x}\)Let \( \frac{3}{5}=cos\theta\)\...
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answered Mar 2, 2013
Toolbox: \( 2tan^{-1}x=-\pi +tan^{-1}\large\frac{2x}{1-x^2} \: if \: x < -1\) \(t...
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