Email
Chat with tutors
logo

Ask Questions, Get Answers

X
 

Answers posted by rvidyagovindarajan_1

917
answers
2
best answers
0 votes
answered Mar 21, 2014
Toolbox:If the order of 2 matrices are equal, their corresponding elements are equal, i.e, if $A_{ij...
0 votes
answered Mar 20, 2014
Toolbox: Projection of $\overrightarrow a$ on $\overrightarrow b$ is $\large\frac{\overrightarrow...
0 votes
answered Mar 20, 2014
<div class="clay6-toolbox"><b>Toolbox:</b><ul><li class="c...
0 votes
answered Mar 20, 2014
Given:$R=\{(a,a^3):\:a\: is\: a\: prime\:number\: less\: than\: 5\}$ $\Rightarrow\:R=\{(2,2^3),(3,3...
0 votes
answered Mar 20, 2014
Toolbox:If $ |A|=x$, then $ |p.A|=p^n.|A|$ where $n$ is order of the matrix $A$.Given: $|3A|=k...
0 votes
answered Mar 20, 2014
$\int\large\frac{dx}{sin^2x\:cos^2x}$Multiplying and dividing by 4=4 $\int\large\frac{dx}{4sin^2x\:...
0 votes
answered Mar 13, 2014
Toolbox:$n^{th}$ term of an A.P$=a+(n-1)d$Sum of $n$ terms of any series, $S_n=\sum t_n$$\sum ( A+...
0 votes
answered Mar 12, 2014
Toolbox:$n^{th}$ term of an A.P$=a+(n-1)d$ $\sum n=\large\frac{n(n+1)}{2}$$\sum n^2=\large\frac{n(n...
0 votes
answered Mar 10, 2014
The given series is $\large\frac{1}{1\times 2}+\frac{1}{2\times 3}+\frac{1}{3\times 4}+..........$S...
0 votes
answered Mar 7, 2014
Toolbox:$n^{th}$ term of an A.P.$=a+(n-1)d$Sum of $n$ terms of any series with $n^{th}$ term $t_n...
0 votes
answered Mar 7, 2014
Toolbox:Sum of $n$ terms of any series $S_n=\sum t_n$$\sum n=\large\frac{n(n+1)}{2}$$\sum n^2=\larg...
0 votes
answered Mar 7, 2014
Toolbox:For any series $\sum t_n=Sum =S_n$$\sum n=1+2+3+.......n=\large\frac{n(n+1)}{2}$$\sum n^2=1^...
0 votes
answered Mar 7, 2014
Toolbox:A.M. between two numbers $a$ and $b= \large\frac{a+b}{2}$G.M. between the two numbers$= ...
0 votes
answered Mar 6, 2014
Toolbox:The A.M. between $a$ and $b$ $=\large\frac{a+b}{2}$The G.M. between $a$ and $b$ $=\s...
0 votes
answered Mar 5, 2014
Toolbox:The sum of the interior angles of $n$ sided polygon = $(n-2).180^{\circ}$The sum of $n$ t...
0 votes
answered Mar 5, 2014
Toolbox:The G.M. between two numbers $a$ and $b$ = $\sqrt {ab}$$(a+b)^2=a^2+b^2+2ab$The solutions ...
0 votes
answered Mar 4, 2014
Toolbox:G.M. $'g'$ between $a$ and $b$ is $\sqrt {ab}$$(x+y)^2=x^2+y^2+2xy$$\large\frac{x^m}{y...
0 votes
answered Mar 4, 2014
Toolbox:$a^{mn}=(a^m)^n$Given that $2$ numbers are inserted between $3$ and $81$ so that the re...
0 votes
answered Mar 3, 2014
Toolbox:$a^{mn}=(a^m)^n$Given that $2$ terms are inserted between $3$ and $81$ to form a G.P.Le...
0 votes
answered Mar 3, 2014
Toolbox:The first four terms of a G.P. are assumed as $a,ar,ar^2,ar^3$$(ab)^m=a^m.b^m$$(a^m)^n=a^...
0 votes
answered Mar 2, 2014
Toolbox:Sum of first $n$ terms of a G.P$=a.\large\frac{1-r^n}{1-r}$Step 1Given that the G.P. has $...
0 votes
answered Mar 2, 2014
Toolbox:$t_n=a.r^{n-1}$General G.P is $a,ar,ar^2,................ar^{n-1}$$1+2+3+.........n=\large\...
0 votes
answered Mar 1, 2014
Toolbox:$n^{th}$ term of a G.P.$=a.r^{n-1}$Given that $p^{th}$ term of a G.P.$=a$$q^{th}$ term$=b...
0 votes
answered Mar 1, 2014
Toolbox:$a^2-b^2=(a-b)(a+b)$$a^3-b^3=(a-b)(a^2+ab+b^2)$Let the four terms in G,P, be $a,ar,ar^2\:\...
0 votes
answered Mar 1, 2014
Given two sequences are$a,ar,ar^2.........ar^n$ ...........(i) and $A,AR,AR^2.............AR^{n-...
0 votes
answered Mar 1, 2014
Given sequences are$2,4,8,16,32$.........(i) and$128,32,8,2,\large\frac{1}{2}$............(ii)Bot...
0 votes
answered Feb 28, 2014
Toolbox:Sum of $n$ terms of a G.P=$a.\large\frac{r^n-1}{r-1}$Given series $S=8+88+888+........$Taki...
0 votes
answered Feb 27, 2014
Toolbox:$n^{th}$ term of a G.P. =$t_n=a.r^{n-1}$To prove $x,y,z$ are in G.P. we have to prove that...
0 votes
answered Feb 27, 2014
Toolbox:$n^{th}$ term of a G.P=$t_n=a.r^{n-1}$Let the G.P. be $a,ar,ar^2........$Given that the su...
0 votes
answered Feb 27, 2014
Toolbox:$n^{th}$ term of a G.P.= $t_n=a.r^{n-1}$Given that in a G.P.first term $a=729$,and $7^{th}$...
0 votes
answered Feb 26, 2014
Let the first $6$ terms of the G.P. be $a,ar,ar^2,ar^3,ar^4,ar^5$It is given that sum of first 3 ter...
0 votes
answered Feb 26, 2014
Toolbox:Sum of $n$ terms of a G.P.=$S_n=a.\large\frac{r^n-1}{r-1}$Given that sum of $n$ terms of th...
0 votes
answered Feb 26, 2014
Toolbox:Assume any three terms of a G.P as $\large\frac{a}{r},$$a,ar$Sum of $n$ terms of a G.P.=$S...
0 votes
answered Feb 26, 2014
Toolbox:$\sum (A+B)=\sum A+\sum B$Sum of $n$ terms of a G.P.$=a.\large\frac{r^n-1}{r-1}$$\sum\limits...
0 votes
answered Feb 26, 2014
Toolbox:Sum of $n$ terms of a G.P.$=S_n=a.\large\frac{1-r^n}{1-r}$ where $a=$ first term and ...
0 votes
answered Feb 26, 2014
Toolbox:Sum of $n$ terms of a G.P=$S_n=a.\large\frac{1-r^n}{1-r}$ where first term=$a$ and common...
0 votes
answered Feb 26, 2014
Toolbox:Sum of $n$ terms of a G.P.=$S_n=a.\large\frac{r^n-1}{r-1}$ where $a=$first term and $r=$...
0 votes
answered Feb 25, 2014
Toolbox:Sum of $n$ terms of a G.P$=S_n=a.\large\frac{1-r^n}{1-r}$Given G.P. is $ 0.15+0.015+0.0015...
0 votes
answered Feb 25, 2014
Toolbox:If $x,y,z$ are in G.P. then common ratio $r=\large\frac{y}{x}=\frac{z}{y}$Given that $-\la...
0 votes
answered Feb 25, 2014
Toolbox:$n^{th}$ term of a G.P$=t_n=a.r^{n-1}$ where $a=1^{st}\:term\:and\:r=common\:ratio.$The gi...
0 votes
answered Feb 25, 2014
Toolbox:$n^{th}$ term of a G.P$=t_n=a.r^{n-1}$ where $a=1^{st}\:term\:and\:r=common\:ratio.$The g...
0 votes
answered Feb 25, 2014
Toolbox:$n^{th}\:term$ of a G.P.$=t_n=a.r^{n-1}$ where $a=1^{st}\:term\:and\:d=common \:ratio.$Giv...
0 votes
answered Feb 25, 2014
Toolbox:$n^{th}\:term$ of a G.P.$=a.r^{n-1}$ where $1^{st}\:term=a$ and $common\: ratio=r$Given: ...
0 votes
answered Feb 25, 2014
Toolbox:$n^{th}$ term of a $G.P.=t_n=a.r^{n-1}$ where $a=1^{st} term,\:\:r=common\:ratio.$Given th...
0 votes
answered Feb 25, 2014
Toolbox:$n^{th}$ tem of a $G.P.=t_n=a.r^{n-1}$ where $1^{st}$ term$ =a$ and common ratio$=r$Give...
0 votes
answered Feb 25, 2014
Toolbox:$n^{th}\:term$ of a $G.P.=t_n=a.r^{n-1}$ where $r$ is common ratio and $a=first\:term$Giv...
0 votes
answered Feb 24, 2014
Toolbox:$n^{th}$ term of an $A.P.=t_n=a+(n-1)d$Given that the first installment is $Rs.100$Each ins...
Home Ask Tuition Questions
Your payment for is successful.
Continue
...