Email
Chat with tutors
logo

Ask Questions, Get Answers

X
 

Answers posted by yamini.v

951
answers
0
best answers
0 votes
answered Mar 31, 2014
Answer : $\;a=b$Since $C_p - C_v = R \rightarrow a = b$
0 votes
answered Mar 31, 2014
Answer : Twice the original valueExplanation :$KE_{average} = \large\frac{3}{2} $$KT\;$ for a single...
0 votes
answered Mar 31, 2014
Answer : $\;457^{0}C$Explanation :$V_{m}=\sqrt{\large\frac{3RT}{M}}$$\large\frac{V_{N_{2}}}{V_{O_{...
0 votes
answered Mar 31, 2014
Answer : $\;H_{2}$Explanation :$V_{rms} = \sqrt{\large\frac{3RT}{M}}$or $\;M=\large\frac{3RT}{V_{r...
0 votes
answered Mar 31, 2014
Answer : $\;11\;RT$Explanation :$U= \large\frac{n_{1}f_{1}}{2}$$RT + \large\frac{n_{2}f_{2}}{2} $$R...
0 votes
answered Mar 27, 2014
Answer : $\;\large\frac{19}{13}$Explanation :$C_{peq} = \large\frac{n_{1}C_{p_{1} }+ n_{2} C_{p_{...
0 votes
answered Mar 27, 2014
Answer: 40%For an isobaric process, $Q = nC_P \Delta T$ and $W = nR \Delta T$Now, $C_P = \large\frac...
0 votes
answered Mar 27, 2014
Answer: $\large\frac{\gamma -1}{\gamma}$For an isobaric process, $Q = nC_P \Delta T$ and $W = nR \De...
0 votes
answered Mar 27, 2014
Answer : 2.69 $\times$ 10$^{16}$$PV = nRT \rightarrow n = \large\frac{PV}{RT}$Number of particles $ ...
0 votes
answered Mar 27, 2014
Answer : 2.01 $ \times$ 10$^{4}$ K$v_{rms} =\sqrt{ \large\frac{ 3RT}{M}}$$ = 11.2 \times 10^3\; m/...
0 votes
answered Mar 27, 2014
Answer : with smaller average speedExplanation :$V_{av} = \sqrt{\large\frac{8RT}{\pi M}}$$M_{O_{2}}...
0 votes
answered Mar 27, 2014
Answer : $\;2V$Explanation :$V_{rms} = \sqrt{\large\frac{3RT}{M}}$$V_{rms}^{'} = \sqrt{\large\frac{...
0 votes
answered Mar 27, 2014
Answer : $\;T_{1} > T_{2}$Explanation :$\large\frac{p}{\rho} = constant = \large\frac{3RT}{M}\;$ ...
0 votes
answered Mar 26, 2014
Answer : $\;426.3K$Explanation :$\sqrt{\large\frac{3RT_{1}}{M_{1}}}=\sqrt{\large\frac{3RT_{2}}{M_{2...
0 votes
answered Mar 26, 2014
Answer : momentumExplanation : At equilibrium, the momentum is conserved and hence zero.
0 votes
answered Mar 26, 2014
Answer : They have a certain constant average speed.Explanation :$V_{av}=\sqrt{\large\frac{8KT}{\pi...
0 votes
answered Mar 26, 2014
Answer : $\;20\%$Explanation :$U/second=\sigma A T^{4}$$\large\frac{\bigtriangleup u}{u}= 4\large\...
0 votes
answered Mar 26, 2014
Answer : $\;10^{3}K$Explanation :By stefan's law energy radiated per second / unit area = $\; \sigm...
0 votes
answered Mar 26, 2014
Answer : $ \;1 : 1$Explanation :$\large\frac{stefan's\;law}{energy\;radiated\;per\;second}\;U_{4}=...
0 votes
answered Mar 26, 2014
Answer : $\; 3.33 \times 10^{-6} \;m$Explanation :$\lambda m T = constant\;\;$ (wein's displacement...
0 votes
answered Mar 25, 2014
Answer : $\;16\;W$Explanation :In series $\;Q_{1}=\large\frac{KA(T_{1}-T_{2})}{2L}$In parallel $Q_{...
0 votes
answered Mar 25, 2014
Answer : $\;K_{1}K_{2}=K_{3}K_{4}$Explanation :Since no heat flows through the central rod , temper...
0 votes
0 votes
answered Mar 24, 2014
Answer : $\;-10^{0}C$Explanation :$\large\frac{T_{H}-T_{C}}{L}=\large\frac{\bigtriangleup T}{L}$$80...
0 votes
answered Mar 24, 2014
Answer : $\;0.00018/^{0}C$Explanation :When 2 liquid columns balance each other , the processes exe...
0 votes
answered Mar 24, 2014
Answer : $\;13.11\;g/C.C$Explanation :$\rho = \large\frac{\rho_{0}}{(1+r_{0}t)}$$=\large\frac{13.6}...
0 votes
0 votes
answered Mar 24, 2014
Answer : $\;60^{\circ}C$Explanation :$\large\frac{\text{Temperature-lower fixed point}}{\text{upper...
0 votes
answered Mar 21, 2014
Answer : $\;546\;K$Explanation : $K-273=C$$K=C+273=2C$$C=273^{0}C\;,K=546 K$
0 votes
answered Mar 21, 2014
Answer : $\;37^{0}C$Explanation :$C=\large\frac{5}{9}\;(F-32)$$=\large\frac{5}{9}\;[98.4-32] \appro...
0 votes
answered Mar 21, 2014
Answer : $\;\large\frac{\pi}{2}$Explanation :Work done = $\;\large\frac{1}{2}\;$ Area of ellipse$...
0 votes
answered Mar 21, 2014
Answer : $\;zero$Explanation :https://clay6.com/mpaimg/1_figure18.PNGABOA is a clockwise processWo...
Home Ask Tuition Questions
Your payment for is successful.
Continue
...